# Line slope calculator 4x-5y=10

**Straight line given by points A[5; 2] and B[10; 6]**

## Calculation:

**Slope-intercept form of line:**y = 0.8x-2

**Canonical form of the line equation:**4x-5y-10 = 0

**Parametric form of the line equation:**

x = 5t+5

y = 4t+2 ; t ∈ R

**Slope:**m = 0.8

**Slope angle of line: φ =**38°39'35″ = 0.6747 rad

**X intercept:**x

_{0}= 2.5

**Y intercept:**y

_{0}= q = -2

**Distance line from the origin:**d

_{0}= 1.5617

**The length of the segment AB: |AB| =**6.4031

**Vector: AB =**(5; 4)

**Normal vector: n =**(4; -5)

**Midpoint of the segment AB: M =**[7.5; 4]

**Perpendicular Bisector equation:**5x+4y-53.5 = 0

**Vector OA = (5; 2) ; |OA| = 5.3852**

**Vector OB = (10; 6) ; |OB| = 11.6619**

**Scalar product OA .OB = 62**

**Angle ∠ AOB = 9°9'44″ = 0.1599 rad**